# Force analysis on both ends of hardware spring

To pull the springs at both ends, the force in the same direction as the acceleration must be greater than the force at the other end. The subtracted part of the two forces just provides the spring for acceleration motion. If the two forces are in the same straight line, isn’t the direction of the resultant force the direction of the larger force? The spring will rotate if it is not in the same straight line. The Hooke’s law is still correct, but the force state of each point of the spring is different, so the overall relationship is not that.
It is recommended to learn Newton’s second law of physics in high school. For example, the left hand does not move and the right hand suddenly pulls. At this time, the right end is immediately stressed, and the degree of deformation is very large, and the middle part will not start to be affected after a period of time (although it is short but some). Relatively small, the left end will be affected later. After a period of rest, the force will be evenly distributed.
You can imagine a 100-meter-long spring. Pulling this end and the other side will definitely not immediately deform. Without deformation, there is no force (Hooke’s law). If only one hand accelerates and the other hand does not accelerate, it is equivalent to the moment when the spring is pulled up every moment.
Accelerating and pulling both hands is equivalent to: the left half of the left end accelerates the middle end (it must be static) without acceleration, and the right half of the right end accelerates the middle end without accelerating. The hand pulling force that accelerates in the same direction and accelerates in the same direction is large. Heli direction. At this time, the force of each point of the spring is uniform, but the deformation is uneven.